Complete exercise: threads_channels
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@@ -22,8 +22,8 @@ fn main() {
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// join handle in a variable called `handle`. Once you've done this you should be able to run
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// the code and see the output from the child thread's expensive sum in the middle of the main
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// thread's processing of letters.
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//
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//let handle = ...
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let handle = thread::spawn(|| expensive_sum(my_vector));
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// While the child thread is running, the main thread will also do some work
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for letter in vec!["a", "b", "c", "d", "e", "f"] {
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@@ -37,63 +37,96 @@ fn main() {
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// to a variable named `result`
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// - Get the i32 out of `result` and store it in a `sum` variable.
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// let result =
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// let sum =
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// println!("The child thread's expensive sum is {}", sum);
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let result = handle.join();
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let sum = result.unwrap();
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println!("The child thread's expensive sum is {}", sum);
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// 3. Time for some fun with channels!
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// - Uncomment the block comment below (Find and remove the `/*` and `*/`).
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// - Create variables `tx` and `rx` and assign them to the sending and receiving ends of an
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// unbounded channel. Hint: An unbounded channel can be created with `channel::unbounded()`
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/*
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// let ...
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let (tx, rx) = channel::unbounded();
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// Cloning a channel makes another variable connected to that end of the channel so that you can
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// send it to another thread. We want another variable that can be used for sending...
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let tx2 = tx.clone();
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// Cloning a channel makes another variable connected to that end of the channel so that you can
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// send it to another thread. We want another variable that can be used for sending...
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let tx2 = tx.clone();
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// 4. Examine the flow of execution of "Thread A" and "Thread B" below. Do you see how their
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// output will mix with each other?
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// - Run this code. Notice the order of output from Thread A and Thread B.
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// - Increase the value passed to the first `sleep_ms()` call in Thread A so that both the
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// Thread B outputs occur *before* Thread A outputs anything.
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// - Run the code again and make sure the output comes in a different order.
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// 4. Examine the flow of execution of "Thread A" and "Thread B" below. Do you see how their
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// output will mix with each other?
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// - Run this code. Notice the order of output from Thread A and Thread B.
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// - Increase the value passed to the first `sleep_ms()` call in Thread A so that both the
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// Thread B outputs occur *before* Thread A outputs anything.
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// - Run the code again and make sure the output comes in a different order.
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// Thread A
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let handle_a = thread::spawn(move || {
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sleep_ms(0);
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tx2.send("Thread A: 1").unwrap();
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sleep_ms(200);
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tx2.send("Thread A: 2").unwrap();
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});
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// Thread A
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let handle_a = thread::spawn(move || {
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sleep_ms(500);
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tx2.send("Thread A: 1").unwrap();
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sleep_ms(200);
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tx2.send("Thread A: 2").unwrap();
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});
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sleep_ms(100); // Make sure Thread A has time to get going before we spawn Thread B
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sleep_ms(100); // Make sure Thread A has time to get going before we spawn Thread B
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// Thread B
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let handle_b = thread::spawn(move || {
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sleep_ms(0);
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tx.send("Thread B: 1").unwrap();
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sleep_ms(200);
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tx.send("Thread B: 2").unwrap();
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});
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// Thread B
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let handle_b = thread::spawn(move || {
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sleep_ms(0);
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tx.send("Thread B: 1").unwrap();
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sleep_ms(200);
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tx.send("Thread B: 2").unwrap();
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});
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// Using a Receiver channel as an iterator is a convenient way to get values until the channel
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// gets closed. A Receiver channel is automatically closed once all Sender channels have been
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// closed. Both our threads automatically close their Sender channels when they exit and the
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// destructors for the channels get automatically called.
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for msg in rx {
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println!("Main thread: Received {}", msg);
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}
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// Using a Receiver channel as an iterator is a convenient way to get values until the channel
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// gets closed. A Receiver channel is automatically closed once all Sender channels have been
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// closed. Both our threads automatically close their Sender channels when they exit and the
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// destructors for the channels get automatically called.
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for msg in rx {
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println!("Main thread: Received {}", msg);
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}
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// 5. Oops, we forgot to join "Thread A" and "Thread B". That's bad hygiene!
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// - Use the thread handles to join both threads without getting any compiler warnings.
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*/
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// 5. Oops, we forgot to join "Thread A" and "Thread B". That's bad hygiene!
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// - Use the thread handles to join both threads without getting any compiler warnings.
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let _ = handle_a.join();
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let _ = handle_b.join();
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// Challenge: Make two child threads and give them each a receiving end to a channel. From the
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// main thread loop through several values and print each out and then send it to the channel.
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// On the child threads print out the values you receive. Close the sending side in the main
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// thread by calling `drop(tx)` (assuming you named your sender channel variable `tx`). Join
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// the child threads.
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let (tx, rx) = channel::unbounded();
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let rx2 = rx.clone();
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let thread_a_handle = thread::spawn(move || {
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for n in rx {
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println!("Thread A received: {}", n);
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sleep_ms(10);
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}
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});
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let thread_b_handle = thread::spawn(move || {
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for n in rx2 {
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println!("Thread B received: {}", n);
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sleep_ms(10);
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}
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});
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for number in vec![
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1,
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2,
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3,
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4,
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5,
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] {
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println!("NUMBER: {}", number);
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let _ = tx.send(number);
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}
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drop(tx);
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let _ = thread_a_handle.join();
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let _ = thread_b_handle.join();
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println!("Main thread: Exiting.")
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}
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